北京化工大学2001参考答案一、选择题(10分)1.D2.B3.B(A因DA不对,C因BC不对,D因AB不对)4.B(C=4-1-1=2,F=2-3+2=1)5.D(Ea=RT2dkkdl6.A(1=6Z+bz1gg=0.509ZZW7)7.B8.C9.D(S由小到大:HeArN2零:S(系统)零;S(环境)零;Gmix零。(4 17min(t=k=-In)t 1-x5.Cu ICu2*(b2=1X 10mol.kg)ll Cu2*(b=1mol.kg)ICuAg IAgCI(s),CI(b=1mol.kg)Il CI(b2=1X10 mol.kg),AgCI(s)IAg6.0=4.54(T=Tbp=55.52/12.23)1+bp三、(12分)1.状态方程pVm=RT(I+bp)试证该气体的U.=bp2证明:dU=TdS-pdV两边恒温下除dV,并引麦克斯韦关系得:4将T1=298k1=0.368Ea=52700k2=2.591代入解得T2=445.4K七、(14分)1.t190708g+LB40XBB2.纯B,在90(=363.2Kp1=101.325kPa在40(=313.2K)p2=0.4101.325kPa引克-克方程:In P2AvH1 1代入解得:vHm=17332J.mol1